I was so angry with my friend; Akindeko, for making me sad since he did not even deem it fit to make it up to me in the exam hall as he promised. Such is life!!!...i was terribly embarrassed because all my mates had finished their papers but I was left alone in the hall looking at my question paper like groundnut.
was a terrible one and I was thinking of how to prepare for tomorrows paper. I got home meeting my parent watching Paloma and Diego but I wasn’t in the mood because I was thinking of how to prepare for tomorrow’s paper.
At night, I
couldn’t eat, I couldn’t drink, I couldn’t sleep, I couldn’t pray, I couldn’t
sit nor stand…I was just lying down and rolling on the floor like a snake
staring at my book for the Next paper…Anyway, I put them in God’s hands because
I cannot ‘kukuma’ kill myself
In the
morning, I went to school prepared but I was kind of confused of what will come
out in the exam…All of a sudden, we all sat down and the scripts were passed
from one person to another. That was how I pick up my pen and I started the
write up by myself…it wasn’t easy though. See what I have written but I don’t
know if I was wrong or right sha….
1. Simplify 6¼ – 32/5
2½ –
13/5
It becomes 25/4
– 17/5 = 57/20 = 31/6
5/2
– 8/5 9/10
ii. The average age of students in a
class is 15years. When the teachers ages of 45 years is added, the average age
now becomes 18. How many students are in the class?
Solution
x = sum of ages of the students
y = total number of the students
x/y
= 15 …i
x + 45 = 18
y + 1
x + 45 = 18y + 18; becomes x = 18y – 27
Therefore; 18y – 27 = 15y
18y – 15y = 27; y = 9
Since the total number of the students is 9, The total sum of ages is x = 15(9) = 135years
Therefore, the number of students in the class 9 and the total number of the ages is 135 years
2. If m = r .
m – y + 2 y + r – 1
make y the subject of the formula
solution
m(y + r – 1) = r(m – y + 2)
my + mr – m = rm – yr + 2r
my + yr = rm + 2r + m – mr
y(m + r) = rm + 2r + m – mr
m + r m + r
The final answer is; y = 2r
+ m
m
+ r
ii. In a school 60% of the girls
and 70% of the boys own a bicycle. If a boy and a girl are selected at random
from the school, find the probability that one of them owns a bicycle.
Solution
60% = Girls has bicycle
70% = Boy has bicycle
40% = Girls dosent have bicycle
30% = Boys dosent have a bicycle
When only one of the owns a bicycle, it becomes
(60/100 × 30/100) + (70/100
× 40/100)
It becomes 18/100 + 28/100
= 23/50
3. If x = – 1, y = – 3, z = – 4 and w = – 7, evaluate x3
– y2
2w – z
Solution
(– 1)3 – (– 3)2 = – 1 – 9 =
– 10 = 1
2(– 7) – (– 4) – 14 + 4 – 10
b. The value of x is (90 – 46) = 440
for the value of y, it becomes;
46 + 44 = 90
therefore, 180 – 90 = 900
4. Solve the inequality; 2(1 – 4x)
– (5 – 3x) ≤ (7 + 9x) – 1
3 2 4 3
Solution
(2 – 8x) – (5 – 3x) ≤ 7 + 9x –
1
3 2 4
3
4
– 16x – 15 + 9x ≤ 21 + 27x –
4
6 12
–
11 – 7x ≤ 17 + 27x
6
12
12(– 11 – 7x)
≤ 6(17 + 27x)
–
132 – 84x ≤ 102 +
162x
–
132 – 102 ≤ 612x
+ 84x
–
234 ≤ 246 it becomes x ≤ – 39
41
b. Tan
20 = x/3; 3 Tan 20 = x
x = 1.0919
3Tan 65 = y
y = 6.4335
the value of the height = x + y
1.0919 + 6.4335 = 7.53m (3 sf)
(Number 5 is a broad question, 10 to 13
involves graph)
6. Every month a family spends 2/5 of its monthly
income on education, 1/6 on clothes, 3/8 on food and saves the rest. If its
monthly income is le 36,000,; how many years will it take to save le 63,000
Solution
Income = x
Education = 2/5x
Cloths = x/6
Food = 3/8x
x – (2/5x
+ x/6 +
3/8x)
x – (96x
+ 40x + 90x)
240
x – 226x
240
240x
– 226x
= 7x
240 120
Therefore 7/120
× 36,000 = 2100
The number
of years it will take to save 63,000 becomes
63000 = 30months which is 21/2
years
2100
7. The
length of chord is 30 × 2 × 22 ×
6400
360 7 = 3350km
ii. R
Cos Q = 6400 × Cos 60 = 3200km
iii. 30 × 2 × 22 × 6400 × Cos 60
360 7 = 1676.19km
10.
X – 3 –
2 – 1
0 1 2 3 4
Y 26 13 4 – 1 – 2 1 8 19
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